{VERSION 3 0 "SUN SPARC SOLARIS" "3.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 } {PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 256 1 {CSTYLE "" -1 -1 "" 1 18 0 0 0 0 0 0 0 0 0 0 0 0 0 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 256 "" 0 "" {TEXT -1 48 "Example 14.4-1. Estimati on of the Solar Constant" }{MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "" 0 " " {TEXT -1 90 "The solar constant is the radiant heat flux entering th e earth's atmosphere from the sun. " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 75 "dQ[12]:=sigma*T[1]^4*cos(theta[1])*dA[1]*dA[2]*cos(theta[2])/(Pi*r[12 ]^2); " }{TEXT -1 33 "Eqn. 14.4-5 and in the discussion" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#>&%#dQG6#\"#7*&*.%&sigmaG\"\"\")&%\"TG6#F+\"\"% \"\"\"-%$cosG6#&%&thetaGF/F+&%#dAGF/F+&F86#\"\"#F+-F36#&F6F:F+F1*&%#Pi G\"\"\")&%\"rGF&\"\"#F1!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 32 "dSC:=dQ[12]/cos(theta[2])/dA[2];" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%$dSCG*&**%&sigmaG\"\"\")&%\"TG6#F(\"\"%\"\"\"-%$cosG6#&%&theta GF,F(&%#dAGF,F(F.*&%#PiG\"\"\")&%\"rG6#\"#7\"\"#F.!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "SC:=int(dSC/dA[1], A[1]); " }{TEXT -1 28 "need to remove dA1 for Maple" }}{PARA 11 "" 1 "" {XPPMATH 20 "6 #>%#SCG*&**%&sigmaG\"\"\")&%\"TG6#F(\"\"%\"\"\"-%$cosG6#&%&thetaGF,F(& %\"AGF,F(F.*&%#PiG\"\"\")&%\"rG6#\"#7\"\"#F.!\"\"" }}}{EXCHG {PARA 0 " > " 0 "" {MPLTEXT 1 0 35 "A[1]:=Pi*d[1]^2/(4*cos(theta[1])); " }{TEXT -1 189 "cos(theta1) can be included because the integral(cos(theta))dA is the area of the sun, which is nearly pi*D1^2/4. For simplicity, we simply remove it after the integral has been calculated." }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>&%\"AG6#\"\"\",$*&*&%#PiGF')&%\"dGF&\"\"#\"\" \"F0-%$cosG6#&%&thetaGF&!\"\"#F'\"\"%" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 3 "SC;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*&*&&%\"qG6#% #b1G\"\"\")&%\"dG6#F*\"\"#\"\"\"F0*$)&%\"rG6#\"#7\"\"#F0!\"\"#F*\"\"% " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "sigma:=q[b1]/T[1]^4;" } }{PARA 11 "" 1 "" {XPPMATH 20 "6#>%&sigmaG*&&%\"qG6#%#b1G\"\"\"*$)&%\" TG6#\"\"\"\"\"%F*!\"\"" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 3 "SC ;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*&*&&%\"qG6#%#b1G\"\"\")&%\"dG6 #F*\"\"#\"\"\"F0*$)&%\"rG6#\"#7\"\"#F0!\"\"#F*\"\"%" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 20 "Diameter of the sun:" }} {PARA 0 "> " 0 "" {MPLTEXT 1 0 19 "d[1]:=8.60e5*miles;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>&%\"dG6#\"\"\",$%&milesG$\"$g)\"\"$" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 29 "Distance between dA1 and dA2:" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "r[12]:=9.29e7*miles;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>&%\"rG6#\"#7,$%&milesG$\"$H*\"\"&" }}}{EXCHG {PARA 0 " " 0 "" {TEXT -1 10 "Heat flux:" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 25 "q [b1]:=2.0e7*Btu/hr/ft^2;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>&%\"qG6#% #b1G,$*&%$BtuG\"\"\"*&%#hrG\"\"\")%#ftG\"\"#F+!\"\"$\"#?\"\"'" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 3 "SC;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#,$*&%$BtuG\"\"\"*&%#hrG\"\"\")%#ftG\"\"#F&!\"\"$\"+w&[[ G%!\"(" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 47 "Which is reasonably clo se to the book's answer." }{MPLTEXT 1 0 0 "" }}}}{MARK "10 0 0" 0 } {VIEWOPTS 1 1 0 1 1 1803 }